If the exterior angles of a pentagon are x^\circ, (x + 5)^\circ, (x + 10)^\circ, (x + 15)^\circ and (x + 20)^\circ, find x
A
118o
B
72o
C
62o
D
36o
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
The sum of the exterior angles of a regular polygon = 360^\circ.
\(\therefore x + (x + 5) + (x + 10) + (x + 15) + (x + 20) = 360^\circ\)
\(5x + 50 = 360^\circ \implies 5x = 360^\circ - 50^\circ = 310^\circ\)
\(x = \frac{310^\circ}{5} = 62^\circ\)
Source: Myschool Past Questions Archive (Record #31419)