The sum of the first n terms of an arithmetic progression is 252. If the first term is -16 and the last term is 72, find the number of terms in the series
A
6
B
7
C
8
D
9
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Using: \(S_n = \frac{n}{2} (a + l)\)
where:- \(S_n\) is the sum of the first \(n\) terms, \(a\) is the first term, \(l\) is the last term.
Given: \(S_n = 252\), a = -16, l = 72
Step 1: Substitute the Known Values
Substituting the values into the sum formula:
\(252 = \frac{n}{2} (-16 + 72)\)
\(252 = \frac{n}{2} \cdot 56\)
\(504 = n \cdot 56\)
Now, divide both sides by 56:
n = \(\frac{504}{56}\) = 9
Thus, the number of terms in the series is: 9
Source: Myschool Past Questions Archive (Record #7775)