3 + 2 + \(\frac{4}{3}\) + \(\frac{8}{9}\) + \(\frac{16}{17}\) + ..... a = 3 r = \(\frac{2}{3}\) s \(\alpha\) = \(\frac{a}{1 - r}\) = \(\frac{3}{1 - \frac{2}{3}}\) = \(\frac{3}{\frac{1}{3}}\) = 3 x 3 = 9