Calculate the length in cm. of the arc of a circle of diameter 8cm which subtends an angle of 22\(\frac{1}{2}\)o at the centre of the circle
A
2\(\pi\)
B
\(\pi\)
C
\(\frac{2}{3}\)
D
\(\frac{\pi}{2}\)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Diameter = 8cm
∴ Radius = 4cm
Length of arc = \(\frac{\theta}{360}\) x 2 \(\pi\)r but Q = 22\(\frac{1}{2}\)
∴ Length \(\frac{22\frac{1}{2}}{360}\) x 2 x \(\pi\) x 4
= \(\frac{22\frac{1}{2} \times 8\pi}{360}\)
= \(\frac{180}{360}\)
= \(\frac{\pi}{2}\)
Source: Myschool Past Questions Archive (Record #31222)