Equation of curve; y = 2x2 - 2x + 3 gradient of curve; \(\frac{dy}{dx}\) = differential coefficient \(\frac{dy}{dx}\) = 4x - 2, for gradient to be 2 ∴ \(\frac{dy}{dx}\) = 2 4x - 2 = 2 4x = 4 ∴ x = 1 When x = 1, y = 2(1)2 - 2(1) + 3 = 2 - 2 + 3 = 5 - 2 = 3 coordinate of the point where the curve; y = 2x2 - 2x + 3 has gradient equal to 2 is (1, 3)