Find the range of \(\frac{1}{6}\), \(\frac{1}{3}\), \(\frac{3}{2}\), \(\frac{2}{3}\), \(\frac{8}{9}\), and \(\frac{4}{3}\)
A
3/4
B
5/6
C
7/6
D
4/3
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
\(\frac{1}{6}\), \(\frac{1}{3}\), \(\frac{3}{2}\), \(\frac{2}{3}\), \(\frac{8}{9}\) and \(\frac{4}{3}\).
L.C.M of the denominators = 36
The fraction now becomes
\(\frac{6}{36}\), \(\frac{12}{36}\), \(\frac{54}{36}\), \(\frac{24}{36}\), \(\frac{32}{36}\), and \(\frac{48}{36}\).
Highest fraction = \(\frac{54}{36}\)
Lowest fraction = \(\frac{6}{36}\)
Range = Highest - Lowest
( \(\frac{54}{36}\)) - ( \(\frac{6}{36}\))
= \(\frac{48}{36}\)
= \(\frac{4}{3}\).
Source: Myschool Past Questions Archive (Record #7718)