2x - y .....(i) x + y.....(ii) from (i) y = 2x - 4 from (ii) y = -x + 2 2x - 4 = -x + 2 x = 2 y = -x + 2 = -2 + 2 = 0 \(x_1\) = 2 \(y_1\) = 0 \(x_2\) = 4 \(y_2\) = 3 Hence, dist. = \(\sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}\) = \(\sqrt{(3 - 0)^2 + (4 - 2)^2}\) = \(\sqrt{3^2 + 2^2}\) = \(\sqrt{13}\)