A cone with a sector angle of 45^\circ is cut out of a circle of radius r cm. Find the base radius of the cone.
A
\(\frac{r}{16}\) cm
B
\(\frac{r}{6}\) cm
C
\(\frac{r}{8}\) cm
D
\(\frac{r}{2}\) cm
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
The formula for the base radius of a cone formed from the sector of a circle = \(\frac{r \theta}{360^\circ}\)
= \(\frac{r \times 45^\circ}{360^\circ}\)
= \(\frac{r}{8} cm\)
Source: Myschool Past Questions Archive (Record #30825)