log4(y - 1) + log4(\(\frac{1}{2}\)x) = 1 log4(y - 1)(\(\frac{1}{2}\)x) \(\to\) (y - 1)(\(\frac{1}{2}\)x) = 4 ........(1) log2(y + 1) + log2x = 2 log2(y + 1)x = 2 \(\to\) (y + 1)x = 22 = 4.....(ii) From equation (ii) x = \(\frac{4}{y + 1}\)........(iii) put equation (iii) in (i) = y (y - 1)[\(\frac{1}{2}(\frac{4}{y - 1}\))] = 4 = 2y - 2 = 4y + 4 2y = -6 y = -3 x = \(\frac{4}{-3 + 1}\) = \(\frac{4}{-2}\) X = 2 therefore x = -2, y = -3