P1 (4, 3), P2 (x, y) y = 2x + 4 .....(1) y = 7 - x .....(2) Substitute (2) in (1) 7 - x = 2x + 4 7 - 4 = 2x + x 3 = 3x x = 1 Substitute in eqn (2) y = 7 - x y = 7 - 1 y = 6 P2 (1, 6) Distance between 2 points is given as D = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\) D = \(\sqrt{(1 - 4)^2 + (6 - 3)^2}\) D = \(\sqrt{(-3)^2 + (3)^2}\) D = \(\sqrt{9 + 9}\) D = \(\sqrt{18}\) D = \(\sqrt{9 \times 2}\) D = \(3\sqrt{2}\)