Using x = \(\frac{\sum x}{N}\) in each case, we get; \(\sum_{6}^{i=1} x_i\) = 10 x 7 = 70 \(\sum_{7}^{i=1} x_i\) = 2 + 4 + 8 + 14 + 16 + 18 = 62 Hence the missing number can be obtained from \(\sum_{6}^{i=1} x_i - \sum_{7}^{i=1} x_i\) = 70 - 62 = 8 So, all the seven numbers are 2, 4, 8, 8, 14, 16, 18 Mode = 8