Evaluate \(\int \sin 2x dx\)
A
cos 2x + k
B
\(\frac{1}{2}\)cos 2x + k
C
\(-\frac{1}{2}\)cos 2x + k
D
-cos 2x + k
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
\(\int \sin 2x dx = \frac{1}{2} (-\cos 2x) + k\)
\(- \frac{1}{2} \cos 2x + k\)
Source: Myschool Past Questions Archive (Record #27029)