For what values of y is the expression \(\frac{6y-1}{y^2 - y-6}\) not defined?
A
\(\frac{1}{6}, \frac{1}{4}\)
B
3, -2
C
-3, 2
D
0,1
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
The expression is not defines when \(y^2\) - y - 6 = 0
=> \(y^2\) - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y
-3 = 0 or y + 2 = 0 => y = 3 or -2
Source: Myschool Past Questions Archive (Record #26705)