Given that the root of an the equation \(2x^2 + (k+2)x+k=0\) is 2, find the value of k
A
-4
B
-2
C
-1
D
\(-\frac{1}{4}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
Substituting for x in the equation
\(2(2)^2 + (k+2)2+k = 0 \Rightarrow 8 +2k + 4 + k =0 \Rightarrow 3k =-12; k=-4\)
Source: Myschool Past Questions Archive (Record #26694)