\(202^2_{three}\)when converted to base ten \(=(202_3)^2\) 202_3 = 2 \(\times 3^2 + 0 \times 3^1 + 2\times 3^0 = 18 + 0 + 2\) =20\(_{ten}; (202_3)^2 = (20)^2_{ten} = 400\) 112\(^2_{three}\)when converted to base ten \(= (112_3)^2\) 112_3 = 1 \(\times 3^2 + 1 \times 3^1 + 2\times 3^0 = 9+3+2=14_{ten}\) (112_3)\(^2 = (14)^2_{ten} = 196_{ten}\) Evaluate \(\Longrightarrow 400-196 = 204\) Reconvert to base three 204 \div 3 = 68 remainder 0 68 \div 3 = 22 remainder 2 22 \div 3 = 7 remainder 1 7 \div 3 = 2 remainder 1 2 \div 3 = 0 remainder 2 = 21120\(_3\)