\(y \propto \frac{1}{\sqrt{x}}\) \(y = \frac{k}{\sqrt{x}}\) When x = 16, y = 2. \(2 = \frac{k}{\sqrt{16}} \implies 2 = \frac{k}{4}\) \(k = 8\) \(y = \frac{8}{\sqrt{x}}\) When y = 24, \(24 = \frac{8}{\sqrt{x}}\) \(\sqrt{x} = \frac{8}{24} = \frac{1}{3}\) \(\therefore x = (\frac{1}{3})^2\) \(x = \frac{1}{9}\)