In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y
Attached Figure / Diagram
A
x
B
\(\frac{x^2}{y}\)
C
\(\frac{y}{x^2}\)
D
\(\frac{y^2}{x}\)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
\(\frac{x}{x+y}=\frac{y}{x+CE}\\
xy + xCE = xy + y^2\\
∴xCE = y^2\\
CE=\frac{y^2}{x}\)
Source: Myschool Past Questions Archive (Record #26417)