The diagram shows the position of three ships A, B and C at sea. B is due north of C such that |AB| = |BC| and the bearing of B from A = 040^\circ. What is the bearing of A from C
Attached Figure / Diagram
A
040o
B
070o
C
110o
D
290o
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
< ABC = 40^\circ (alternate angles)
\(\therefore\) < ACB = \(\frac{180^\circ - 40^\circ}{2}\)
= 70^\circ
\(\therefore\) Bearing of A from C = 360^\circ - 70^\circ
= 290^\circ
Source: Myschool Past Questions Archive (Record #26402)