\(\frac{8^{\frac{2}{3}} \times 27^{\frac{-1}{3}}}{64^{\frac{1}{3}}}\) Calculating each part: 1. \(8 = 2^3 \Rightarrow 8^{\frac{2}{3}} = 4\) 2. \(27 = 3^3 \Rightarrow 27^{\frac{-1}{3}} = \frac{1}{3}\) 3. \(64 = 4^3 \Rightarrow 64^{\frac{1}{3}} = 4\) Now substituting these values: \(\frac{4 \times \frac{1}{3}}{4} = \frac{1}{3}\) Thus, the simplified expression is: \(\frac{1}{3}\)