O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42o and ∠QTR = 64o; Find ∠QRT
Attached Figure / Diagram
A
68o
B
64o
C
42o
D
32o
E
22o.
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
TQR = 90 - 42 = 48o
QRT = 180 - (64 - 48)
= 180 - 112
= 68o
Source: Myschool Past Questions Archive (Record #23883)