\(\int 2(2x - 3)^{\frac{2}{3}} \mathrm d x\) Let \(u = 2x - 3\) \(\mathrm d u = 2 \mathrm d x\) = \(\int u^{\frac{2}{3}} \mathrm d u\) = \(\frac{u^{\frac{5}{3}}}{\frac{5}{3}} + k\) = \(\frac{3}{5} (2x - 3)^{\frac{5}{3}} + k\)