In the diagram above, TRQ is a straight line. Find p, if p = \(\frac{1}{3}\)(a + b + c)
Attached Figure / Diagram
A
45o
B
60o
C
90o
D
120sup>o
E
150o
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
a + b + c + p = 180 (sum of angles on a straight line)
But p = \(\frac{1}{3}\)(a + b + c), Then, (a + b + c) = 3p
3p + p = 180
4p = 180
p = \(\frac{180}{4}\) = 45º
Source: Myschool Past Questions Archive (Record #23818)