The given central angle of \(120^\circ\) corresponds to the minor arc The central angle corresponding to the major arc is therefore \(360^\circ - 120^\circ = 240^\circ.\) The length of an arc of a circle of radius \(r\) that subtends an angle \(\theta\) (in degrees) at the centre is given by \(\frac{\theta}{360^\circ} \times 2\pi r.\) Substitute \(r = 14\) cm and \(\theta = 240^\circ\): \(\frac{240}{360} \times 2\pi \times 14 = \frac{2}{3} \times 28\pi = \frac{56\pi}{3}\ \text{cm}.\) = 58.67 cm