Using common ratios \(\frac{\text{x}}{\frac{16}{9}}\) = \(\frac{1}{\text{x}}\) x\(^2\) = \(\frac{16}{9}\) x = \(\frac{4}{3}\) If x = \(\frac{4}{3}\) Then, the common ratio = \(\frac{3}{4}\) y = ar\(^3\) = \(\frac{16}{9}\) x (\(\frac{3}{4}\))\(^3\) y = \(\frac{16}{9}\) x \(\frac{27}{64}\) = \(\frac{3}{4}\) Therefore, the product of x and y = \(\frac{4}{3}\) x \(\frac{3}{4}\) = 1