Solve x\(^2\) + 3x - 4 \le 0
A
-4 \(\geq\) x \(\geq\) 1
B
4 \(\leq\) x \(\leq\) - 1
C
4 \(\geq\) x \(\geq\) 1
D
\(- 4 \leq x \leq 1\)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
To solve \(x^2 + 3x - 4 \leq 0\):
Factorize: \((x + 4)(x - 1) \leq 0\)
Roots: \(x = -4\), \(x = 1\)
Solution: \(-4 \leq x \leq 1\) .
Source: Myschool Past Questions Archive (Record #74193)