To find the inverse of the matrix \(A = \begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix}\) We can use the formula for the inverse of a \( 2 \times 2 \) matrix: \(A^{-1} = \frac{1}{ad - bc} \begin{pmatrix} d & -b \\ -c & a \end{pmatrix}\) where \( A = \begin{pmatrix} a & b \\ c & d \end{pmatrix} \). Identify \( a, b, c, d \)} In our matrix, we have: \(a = 2, \quad b = 1, \quad c = 1, \quad d = 1\) Calculate the determinant \( ad - bc \) Calculating the determinant: \(ad - bc = (2)(1) - (1)(1) = 2 - 1 = 1\) Calculate the inverse: Now substituting into the formula for the inverse: \(A^{-1} = \frac{1}{1} \begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix} = \begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix}\) Thus, the inverse of the matrix \( \begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix} \) is \(\begin{pmatrix} 1 & -1 \\ -1 & 2 \end{pmatrix}\)