In the diagram above, JKL is a tangent to the circle GHIK at K. Find the value of the angle marked x
Attached Figure / Diagram
A
93º
B
55º
C
42º
D
23º
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
\(\angle\)KGL = 87º (exterior angle of a cyclic quadrilateral)
\(\angle\)KGL + \(\angle\)GLK + \(\angle\)LKG = 180º
87º + x + 38º = 180º
x = 180 - 87 - 38 = 55º
Source: Myschool Past Questions Archive (Record #71826)