In the diagram above, AB//CD, the bisector of ∠BAC and ∠ACD meet at E. Find the value of ∠AEC
Attached Figure / Diagram
A
30o
B
45o
C
60o
D
75o
E
90o
Verified Correct Answer: E.
Step-by-Step Mathematical Solution
Ae is a bisector of BAC => EAC = 45o
CE is the bisector of ACD => ACE = 45o
AEC = 180o - [EAC + ACE]
= 180o - (45o + 45o) = 180o - 90o = 90o
Source: Myschool Past Questions Archive (Record #23777)