If log\(_3^{2x - 1}\) = 5, find the value of x
A
8
B
16
C
64
D
122
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
log\(_3^{2x - 1}\) = 5 in index form becomes 3\(^5\) = 2x - 1
2x - 1 = 243
2x = 243 + 1 = 244
x = \(\frac{244}{2}\) = 122
Source: Myschool Past Questions Archive (Record #71765)