Given \(\tan \theta = \frac{8}{15}\) \(\sin \theta = \frac{8}{17}, \quad \cos \theta = \frac{15}{17}\) from pythagora's theorem. To find \(\frac{\sin \theta - \cos \theta}{\sin^2 \theta - \sin \theta}\) Numerator → \(\sin \theta - \cos \theta = \frac{8}{17} - \frac{15}{17} = \frac{-7}{17}\) Denominator → \(\sin^2 \theta = \left(\frac{8}{17}\right)^2 = \frac{64}{289}, \quad \sin^2 \theta - \sin \theta = \frac{64}{289} - \frac{136}{289} = \frac{-72}{289}\) \(\frac{\frac{-7}{17}}{\frac{-72}{289}} = \frac{7 \times 289}{17 \times 72} = \frac{119}{72}\)