In the diagram above; O is the centre of the circle and |BD| = |DC|. If ∠DCB = 35^\circ, find ∠BAO.
Attached Figure / Diagram
A
20o
B
25o
C
30o
D
35o
E
40o
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
< DBC = 35^\circ (base angles of an isosceles triangle)
< CDB = 180^\circ - (35^\circ + 35^\circ)
= 110^\circ
< ADB = 70^\circ; < ABD = 90^\circ(< in a semi-circle)
\(\therefore\) < BAO = 180^\circ - (70^\circ + 90^\circ)( sum of
Source: Myschool Past Questions Archive (Record #23748)