In how many ways can 2 students be selected from a group of 5 students in a debating competition?
A
25 ways
B
10 ways
C
15 ways
D
20 ways
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
\(In\hspace{1mm} ^{5}C_{2}\hspace{1mm}ways\hspace{1mm}\)
=\(\frac{5!}{(5-2)!2!}\)
=\(\frac{5!}{3!2!}\)
=\(\frac{5\times4\times3!}{3!\times2\times1}\)
=10 ways.
Source: Myschool Past Questions Archive (Record #60619)