Given that x is directly proportional to y and inversely proportional to Z, x = 15 when y = 10 and Z = 4, find the equation connecting x, y and z
A
x = \(\frac{6y}{z}\)
B
x = \(\frac{12y}{z}\)
C
x = \(\frac{3y}{z}\)
D
x = \(\frac{3y}{2z}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
\(x\) x \(\frac{y}{z}\)
x = \(\frac{ky}{z}\)
15 = \(\frac{10k}{4}\)
\(\frac{60}{10}\) = k = 6
Therefore; x = \(\frac{6y}{z}\)
Source: Myschool Past Questions Archive (Record #58302)