Find the equation of a straight line passing through the point (1, -5) and having gradient of \(\frac{3}{4}\)
A
3x + 4y - 23 = 0
B
3x + 4y +23 = 0
C
3x - 4y +23 = 0
D
3x - 4y - 23 = 0
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
\(\frac{3}{4} = \frac{y + 5}{x - 1}\)
3(x - 1) = 4(y + 5)
3x - 3 = 4y + 20
3x - 4y - 23 = 0
Source: Myschool Past Questions Archive (Record #57338)