Gradient of line = \(\frac{\text{Change in y}}{\text{Change in x}}\) = \(\frac{y_2 - Y}{x_2 - x}\) y\(_2\) = 0\(_1\) Y\(_1\) = 4 x\(_2\) = 3 and x\(_1\) = 0 \(\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}\) Equation of straight line y = mx + c Where m = gradient and c = y intercept = 4 y = -\(\frac{4}{3}\)x + 4 multiply through by 3 3y = -4x + 12