(a) finding a = 10\(^{1.3010}\) and b = 10\(^{1.4771}\) Then, ab = 10\(^{1.3010}\) x 10\(^{1.4771}\) = 10\(^{2.4771}\) = 599.9 (b)(i) they were expected to find < ABC = 180^\circ - 62^\circ = 118^\circ Exterior < AOC a 2 x 118^\circ - 236^\circ (< at centre is twice angle at the circumference) Interior < AOC = 360^\circ - 236^\circ = 124^\circ(angle at a point) as required. (b)(ii) < BAC in 180^\circ - 39^\circ - 118^\circ = 23^\circ (sum of angles of a triangle)