In the diagram above, O is the centre of the circle ABC, < ABO = 26^\circ and < BOC = 130^\circ. Calculate < AOC.
Attached Figure / Diagram
A
26°
B
13°
C
80°
D
102°
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
< BAC = \(\frac{130}{2}\) (angle subtended at the centre)
< BAC = 65^\circ
Also, x = 26^\circ (theorem)
y = 65^\circ - 26^\circ = 39^\circ
< AOC = 180^\circ - (39^\circ + 39^\circ)
= 102^\circ
Source: Myschool Past Questions Archive (Record #55366)