The angle subtended at the centre by a chord of a circle radius 6cm is 120^\circ. Find the length of the chord.
A
3cm
B
6cm
C
\(4\sqrt{2}\) cm
D
\(3\sqrt{3}\) cm
E
\(6\sqrt{3}\) cm
Verified Correct Answer: E.
Step-by-Step Mathematical Solution
\(\frac{r}{6} = \sin 60 \)
\(r = 6 \sin 60\)
= \(6 \times \frac{\sqrt{3}}{2}\)
= \(3\sqrt{3}\)
Chord = 2r = \( 2 \times 3\sqrt{3}\)
= \(6\sqrt{3}\)
Source: Myschool Past Questions Archive (Record #23506)