simplify; 2lo\(g_3\) 6 + lo\(g_3\) 12 - lo\(g_3\) 16
A
2
B
3
C
2 - 2log32
D
3 - log32
E
4 - log32
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
2lo\(g_3\) 6 + lo\(g_3\) 12 - lo\(g_3\) 16
= \(\log_3 6^2 + \log_3 12 - \log_3 16\)
= \(\log_{3} (\frac{36 \times 12}{16})\)
= \(\log_{3} (27)\)
= \(\log_{3} 3^3\)
= \(3 \log_{3} 3\)
= 3
Source: Myschool Past Questions Archive (Record #23468)