In the diagram above, |QR| = 12cm and |QS| = 10cm. If ∠PQR = 90^\circ, ∠RSQ = 90^\circ and PSQ is a straight line, find |PS|
Attached Figure / Diagram
A
3.3cm
B
4.4cm
C
5cm
D
5.5cm
E
6.6cm
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
\(\frac{PQ}{RQ} = \frac{RQ}{SQ}\) (Similar triangles)
\(\therefore \frac{PS + 10}{12} = \frac{12}{10}\)
\(10 (PS + 10) = 12 \times 12\)
\(10 PS + 100 = 144 \implies 10 PS = 44\)
\(PS = 4.4 cm\)
Source: Myschool Past Questions Archive (Record #23207)