In the diagram above, O is the center of the circle QOR is a diameter and ∠PSR is 37^\circ. Find ∠PRQ
Attached Figure / Diagram
A
37o
B
53o
C
65o
D
127o
E
147o
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
Construction: Join PQ.
Then < RSP = 37^\circ = < RQP (angles on the same segment)
But < RPQ = 90^\circ (angle in a semi-circle)
\(\therefore\) < PRQ = 180^\circ - (90^\circ + 37^\circ)
= 53^\circ
Source: Myschool Past Questions Archive (Record #23161)