In the diagram above PQT is a tangent to the circle QRS at Q. Angle QTR = 48^\circ and ∠QRT = 95^\circ. Find ∠QSR
Attached Figure / Diagram
A
48o
B
45o
C
37o
D
32o
E
30o
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
∠RQT = 180^\circ - (95^\circ + 48^\circ) = 37^\circ
∠OQR = 90^\circ - 37^\circ = 53^\circ
∠QOR = 180^\circ - (53^\circ + 53^\circ) = 74^\circ
QSR = 74^\circ/2 = 37^\circ
Source: Myschool Past Questions Archive (Record #23157)