1/3 \pir\(^2\) x 9 = 1848 3 x \pir2 = 1848 r2 = 1848/3 x 7/22 r = 14 \(\text{Volume of a cone} = \frac{1}{3} \pi r^2 h\) \(\frac{1}{3} \times \frac{22}{7} \times r^2 \times 9 = 1848\) \(r^2 = \frac{1848 \times 7}{22 \times 3}\) \(r^2 = 196 \therefore r = 14cm\)