In the diagram above, O is the center of the circle, |SQ| = |QR| and ∠PQR = 68^\circ. Calculate ∠PRS
Attached Figure / Diagram
A
34o
B
45o
C
56o
D
62o
E
68o
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
From the figure, < PQR = 68^\circ
\(\therefore\) < QRS = < QSR = \(\frac{180 - 68}{2}\) (base angles of an isos. triangle)
= 56^\circ
\(\therefore\) < PRS = 90^\circ - 56^\circ = 34^\circ (angles in a semi-circle)
Source: Myschool Past Questions Archive (Record #23113)