Two groups of male students cast their vote on a particular proposal. The results are as follows:
In favor
Against
Group A
128
32
Group B
96
48
If a student is chosen at random, what is probability that he is against the proposal?
A
3/19
B
4/19
C
5/19
D
9/19
E
10/19
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
Probability that the student is against the proposal
= \(\frac{32 + 48}{128 + 32 + 96 + 48}\)
= \(\frac{80}{304}\)
= \(\frac{5}{19}\)
Source: Myschool Past Questions Archive (Record #22702)