The bearing of a point X from a point Y is 074^\circ. What is the bearing of Y from X?
A
106o
B
146o
C
164o
D
254o
E
286o
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
< YXS = 74^\circ (alternate angles, N\(_1\) S\(_1\) // N\(_2\) S\(_2\))
N\(_2\) E\(_2\) S\(_2\) = 180^\circ
\(\therefore\) Bearing of Y from X = 180^\circ + 74^\circ
= 254^\circ
Source: Myschool Past Questions Archive (Record #22696)