sin\theta = \(\frac{1}{2}\) and cos\theta = -\(\frac{\sqrt{3}}{2}\), what is the value of \theta?
A
30 0
B
60 0
C
90 o
D
120 o
E
150 o
Verified Correct Answer: E.
Step-by-Step Mathematical Solution
In the 2nd Quadrant, SINE is the only Positive.
Where \theta is 30 for the first quadrant and
150 in the 2nd quadrant, which makes COSINE negative
Sin \theta = \(\frac{1}{2}\)
\theta = Sin\(^{-1}(\frac{1}{2}\)) = 30º which is positive in the first quadrant
Sin 30 = Sin 150, i.e, (180 - 30), which is also positive in the second quadrant.
BUT Cos \theta = -\(\frac{\sqrt{3}}{2}\)
\theta = Cos\(^{-1}\)(-\(\frac{\sqrt{3}}{2}\)) = 150º which is in the second quadrant but negative
Hence, \theta = 150º
Source: Myschool Past Questions Archive (Record #22418)