In the diagram above O is the center of the circle, if ∠PAQ = 75o, what is the value of ∠PBQ?
Attached Figure / Diagram
A
15o
B
75o
C
105o
D
150o
E
210o
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
< PBQ = 180^\circ - 75^\circ (opp angles of a cyclic quadrilateral)
= 105^\circ
Source: Myschool Past Questions Archive (Record #22402)