The times taken for iodine to be liberated in the reaction between sodium thiosulphate and hydrochloric acid at various temperature are as follows. These results suggest that
Attached Figure / Diagram
A
for a 10o rise in temperature, rate of reaction is double
B
for a 10 o rise in temperature, rate of reaction is halved
C
time taken for iodine to appear does not depend on temperature
D
for a 10 o rise in temperature rate of reaction is tripled
Verified Correct Answer: A.
Chemical Principles & Mechanism
The iodine liberation process is significantly affected by the amount of acid, that of potassium iodide added, the waiting time for the liberation, and light; therefore, the process plays a key role for the accuracy of the titration results.
For a 10\(^0\) rise in temperature, time of reaction is halved i.e as temperature increases from 25 - 35, time of reaction is halved from 72 to 36.
However, recall that rate of reaction = \(\frac{1}{time of reaction}\)
⇒ They are inversely proportional. Which means for a 10\(^0\) rise in temperature, if time of reaction is halved, then rate of reaction will be doubled.
Source: WAEC / JAMB / NECO Classroom Archive (Record #31380)