2H\(_2\) + O\(_2\) → 2H\(_2\)O
From the equation above, calculate the volume of unreacted oxygen gas if a mixture of 50cm\(^3\) of hydroden and 75cm\(^3\) of oxygen are involved
A
85cm\(^3\)
B
50cm\(^3\)
C
125cm\(^3\)
D
55cm\(^3\)
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
Since 2 mol H\(_2\) reacted with 1 mol of O\(_2\)
: 50cm\(^3\) of hydrogen reacted with 25cm\(^3\) of oxygen
Remainder oxygen = Supplied amount - Reacted amount → 75cm\(^3\) - 25cm\(^3\)
= 50cm\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #64961)